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14012433055 = 53347837313
BaseRepresentation
bin11010000110011010…
…01100001010011111
31100011112212100112001
431003031030022133
5212144140324210
610234235023131
71004145500335
oct150315141237
940145770461
1014012433055
115a40720395
12287089aaa7
13142407300a
1496cdd1b55
1557028c03a
hex34334c29f

14012433055 has 8 divisors (see below), whose sum is σ = 16819963632. Its totient is φ = 11206583808.

The previous prime is 14012433049. The next prime is 14012433067. The reversal of 14012433055 is 55033421041.

14012433055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14012433055 - 27 = 14012432927 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 401922 + ... + 435391.

It is an arithmetic number, because the mean of its divisors is an integer number (2102495454).

Almost surely, 214012433055 is an apocalyptic number.

14012433055 is a deficient number, since it is larger than the sum of its proper divisors (2807530577).

14012433055 is an equidigital number, since it uses as much as digits as its factorization.

14012433055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 840665.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 14012433055 its reverse (55033421041), we get a palindrome (69045854096).

The spelling of 14012433055 in words is "fourteen billion, twelve million, four hundred thirty-three thousand, fifty-five".

Divisors: 1 5 3347 16735 837313 4186565 2802486611 14012433055