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140125103 = 7110211933
BaseRepresentation
bin10000101101000…
…10001110101111
3100202200002111122
420112202032233
5241333000403
621523211155
73321020666
oct1026421657
9322602448
10140125103
1172108078
123ab16abb
1323052281
1414877ddd
15c47d838
hex85a23af

140125103 has 8 divisors (see below), whose sum is σ = 142311456. Its totient is φ = 137944800.

The previous prime is 140125087. The next prime is 140125109. The reversal of 140125103 is 301521041.

140125103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140125103 - 24 = 140125087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140125109) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71525 + ... + 73457.

It is an arithmetic number, because the mean of its divisors is an integer number (17788932).

Almost surely, 2140125103 is an apocalyptic number.

140125103 is a deficient number, since it is larger than the sum of its proper divisors (2186353).

140125103 is a wasteful number, since it uses less digits than its factorization.

140125103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3025.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 140125103 is about 11837.4449523535. Note that the first 3 decimals coincide. The cubic root of 140125103 is about 519.4040299932.

Adding to 140125103 its reverse (301521041), we get a palindrome (441646144).

The spelling of 140125103 in words is "one hundred forty million, one hundred twenty-five thousand, one hundred three".

Divisors: 1 71 1021 1933 72491 137243 1973593 140125103