Base | Representation |
---|---|
bin | 1000001010000000100… |
… | …0111111000001110111 |
3 | 111101200121011020110101 |
4 | 2002200020333001313 |
5 | 4243434132211401 |
6 | 144212311134531 |
7 | 13060305325522 |
oct | 2024010770167 |
9 | 441617136411 |
10 | 140125663351 |
11 | 54477313953 |
12 | 231a7974447 |
13 | 102a191c8cb |
14 | 6ad41bdbb9 |
15 | 39a1c95101 |
hex | 20a023f077 |
140125663351 has 4 divisors (see below), whose sum is σ = 143384399752. Its totient is φ = 136866926952.
The previous prime is 140125663273. The next prime is 140125663397. The reversal of 140125663351 is 153366521041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140125663351 - 217 = 140125532279 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 140125663351.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140125613351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1629368136 + ... + 1629368221.
It is an arithmetic number, because the mean of its divisors is an integer number (35846099938).
Almost surely, 2140125663351 is an apocalyptic number.
140125663351 is a deficient number, since it is larger than the sum of its proper divisors (3258736401).
140125663351 is an equidigital number, since it uses as much as digits as its factorization.
140125663351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3258736400.
The product of its (nonzero) digits is 64800, while the sum is 37.
The spelling of 140125663351 in words is "one hundred forty billion, one hundred twenty-five million, six hundred sixty-three thousand, three hundred fifty-one".
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