Base | Representation |
---|---|
bin | 1100101111101010100111… |
… | …0011110111011011100101 |
3 | 1211121122002022102122002111 |
4 | 3023322221303313123211 |
5 | 3314042142224443240 |
6 | 45445255333441021 |
7 | 2644260000650413 |
oct | 313725163673345 |
9 | 54548068378074 |
10 | 14013032265445 |
11 | 45129914385a4 |
12 | 16a39a01a0171 |
13 | 7a8566c11b15 |
14 | 36633d1d62b3 |
15 | 1947a00c51ea |
hex | cbea9cf76e5 |
14013032265445 has 16 divisors (see below), whose sum is σ = 16910165180160. Its totient is φ = 11147412501184.
The previous prime is 14013032265431. The next prime is 14013032265473. The reversal of 14013032265445 is 54456223031041.
It is a cyclic number.
It is not a de Polignac number, because 14013032265445 - 25 = 14013032265413 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14013032265398 and 14013032265407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27200724 + ... + 27711106.
It is an arithmetic number, because the mean of its divisors is an integer number (1056885323760).
Almost surely, 214013032265445 is an apocalyptic number.
It is an amenable number.
14013032265445 is a deficient number, since it is larger than the sum of its proper divisors (2897132914715).
14013032265445 is a wasteful number, since it uses less digits than its factorization.
14013032265445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 541244.
The product of its (nonzero) digits is 345600, while the sum is 40.
Adding to 14013032265445 its reverse (54456223031041), we get a palindrome (68469255296486).
The spelling of 14013032265445 in words is "fourteen trillion, thirteen billion, thirty-two million, two hundred sixty-five thousand, four hundred forty-five".
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