Base | Representation |
---|---|
bin | 11111110111001101000011… |
… | …100110110000110011101100 |
3 | 200101011120211221210120122111 |
4 | 133313031003212300303230 |
5 | 121331414422220421302 |
6 | 1214012120512453404 |
7 | 41342164113243643 |
oct | 3767150346606354 |
9 | 611146757716574 |
10 | 140133032201452 |
11 | 407180a3465194 |
12 | 13872878b4a264 |
13 | 6026646862774 |
14 | 268669138235a |
15 | 11302ad6550d7 |
hex | 7f73439b0cec |
140133032201452 has 12 divisors (see below), whose sum is σ = 253689110020080. Its totient is φ = 67650429338576.
The previous prime is 140133032201443. The next prime is 140133032201453. The reversal of 140133032201452 is 254102230331041.
It is a super-3 number, since 3×1401330322014523 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (140133032201453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 604021690408 + ... + 604021690639.
It is an arithmetic number, because the mean of its divisors is an integer number (21140759168340).
Almost surely, 2140133032201452 is an apocalyptic number.
It is an amenable number.
140133032201452 is a deficient number, since it is larger than the sum of its proper divisors (113556077818628).
140133032201452 is a wasteful number, since it uses less digits than its factorization.
140133032201452 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1208043381080 (or 1208043381078 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 140133032201452 its reverse (254102230331041), we get a palindrome (394235262532493).
The spelling of 140133032201452 in words is "one hundred forty trillion, one hundred thirty-three billion, thirty-two million, two hundred one thousand, four hundred fifty-two".
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