Base | Representation |
---|---|
bin | 11010000110100001… |
… | …11011100001001111 |
3 | 1100011121201011101011 |
4 | 31003100323201033 |
5 | 212144413212310 |
6 | 10234312030051 |
7 | 1004160022546 |
oct | 150320734117 |
9 | 40147634334 |
10 | 14013413455 |
11 | 5a4122aa38 |
12 | 2871092327 |
13 | 1424327332 |
14 | 96d1a915d |
15 | 5703d278a |
hex | 34343b84f |
14013413455 has 4 divisors (see below), whose sum is σ = 16816096152. Its totient is φ = 11210730760.
The previous prime is 14013413423. The next prime is 14013413459. The reversal of 14013413455 is 55431431041.
14013413455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14013413455 - 25 = 14013413423 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14013413459) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1401341341 + ... + 1401341350.
It is an arithmetic number, because the mean of its divisors is an integer number (4204024038).
Almost surely, 214013413455 is an apocalyptic number.
14013413455 is a deficient number, since it is larger than the sum of its proper divisors (2802682697).
14013413455 is an equidigital number, since it uses as much as digits as its factorization.
14013413455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2802682696.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 14013413455 its reverse (55431431041), we get a palindrome (69444844496).
The spelling of 14013413455 in words is "fourteen billion, thirteen million, four hundred thirteen thousand, four hundred fifty-five".
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