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14013414203 = 47298157749
BaseRepresentation
bin11010000110100001…
…11011101100111011
31100011121201012101212
431003100323230323
5212144413223303
610234312033335
71004160024665
oct150320735473
940147635355
1014013414203
115a41230558
12287109284b
131424327789
1496d1a9535
155703d2ad8
hex34343bb3b

14013414203 has 4 divisors (see below), whose sum is σ = 14311572000. Its totient is φ = 13715256408.

The previous prime is 14013414199. The next prime is 14013414209. The reversal of 14013414203 is 30241431041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14013414203 - 22 = 14013414199 is a prime.

It is a super-3 number, since 3×140134142033 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14013414209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149078828 + ... + 149078921.

It is an arithmetic number, because the mean of its divisors is an integer number (3577893000).

Almost surely, 214013414203 is an apocalyptic number.

14013414203 is a deficient number, since it is larger than the sum of its proper divisors (298157797).

14013414203 is an equidigital number, since it uses as much as digits as its factorization.

14013414203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 298157796.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14013414203 its reverse (30241431041), we get a palindrome (44254845244).

The spelling of 14013414203 in words is "fourteen billion, thirteen million, four hundred fourteen thousand, two hundred three".

Divisors: 1 47 298157749 14013414203