14013432233041 has 4 divisors (see below), whose sum is σ = 14013473380452. Its totient is φ = 14013391085632.

The previous prime is 14013432233033. The next prime is 14013432233113. The reversal of 14013432233041 is 14033223431041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1003733478225 + 13009698754816 = 1001865^2 + 3606896^2 .

It is a cyclic number.

It is not a de Polignac number, because 14013432233041 - 2³ = 14013432233033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14013432232994 and 14013432233012.

It is not an unprimeable number, because it can be changed into a prime (14013432233441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20058556 + ... + 20745421.

It is an arithmetic number, because the mean of its divisors is an integer number (3503368345113).

Almost surely, 2^{14013432233041} is an apocalyptic number.

It is an amenable number.

14013432233041 is a deficient number, since it is larger than the sum of its proper divisors (41147411).

14013432233041 is an equidigital number, since it uses as much as digits as its factorization.

14013432233041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41147410.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 14013432233041 its reverse (14033223431041), we get a palindrome (28046655664082).

The spelling of 14013432233041 in words is "fourteen trillion, thirteen billion, four hundred thirty-two million, two hundred thirty-three thousand, forty-one".