Base | Representation |
---|---|
bin | 1100101111101100000110… |
… | …1001100111110010011001 |
3 | 1211121200010012001002120211 |
4 | 3023323001221213302121 |
5 | 3314044002122424423 |
6 | 45445403142251121 |
7 | 2644302625426045 |
oct | 313730151476231 |
9 | 54550105032524 |
10 | 14013432233113 |
11 | 4513077191195 |
12 | 16a3a92126aa1 |
13 | 7a85cba41791 |
14 | 36637a38d025 |
15 | 1947c527e10d |
hex | cbec1a67c99 |
14013432233113 has 2 divisors, whose sum is σ = 14013432233114. Its totient is φ = 14013432233112.
The previous prime is 14013432233033. The next prime is 14013432233117. The reversal of 14013432233113 is 31133223431041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13987360641024 + 26071592089 = 3739968^2 + 161467^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14013432233113 is a prime.
It is not a weakly prime, because it can be changed into another prime (14013432233117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006716116556 + 7006716116557.
It is an arithmetic number, because the mean of its divisors is an integer number (7006716116557).
Almost surely, 214013432233113 is an apocalyptic number.
It is an amenable number.
14013432233113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14013432233113 is an equidigital number, since it uses as much as digits as its factorization.
14013432233113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 14013432233113 its reverse (31133223431041), we get a palindrome (45146655664154).
The spelling of 14013432233113 in words is "fourteen trillion, thirteen billion, four hundred thirty-two million, two hundred thirty-three thousand, one hundred thirteen".
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