14014042134333 has 4 divisors (see below), whose sum is σ = 18685389512448. Its totient is φ = 9342694756220.

The previous prime is 14014042134307. The next prime is 14014042134413. The reversal of 14014042134333 is 33343124041041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14014042134333 - 2²² = 14014037940029 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14014042134294 and 14014042134303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14014042136333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335673689053 + ... + 2335673689058.

It is an arithmetic number, because the mean of its divisors is an integer number (4671347378112).

Almost surely, 2^{14014042134333} is an apocalyptic number.

It is an amenable number.

14014042134333 is a deficient number, since it is larger than the sum of its proper divisors (4671347378115).

14014042134333 is an equidigital number, since it uses as much as digits as its factorization.

14014042134333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4671347378114.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 14014042134333 its reverse (33343124041041), we get a palindrome (47357166175374).

The spelling of 14014042134333 in words is "fourteen trillion, fourteen billion, forty-two million, one hundred thirty-four thousand, three hundred thirty-three".