1401441201331 has 4 divisors (see below), whose sum is σ = 1407024632664. Its totient is φ = 1395857770000.

The previous prime is 1401441201311. The next prime is 1401441201337. The reversal of 1401441201331 is 1331021441041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1401441201331 - 2¹⁵ = 1401441168563 is a prime.

It is a super-2 number, since 2×1401441201331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1401441201296 and 1401441201305.

It is not an unprimeable number, because it can be changed into a prime (1401441201337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2791715290 + ... + 2791715791.

It is an arithmetic number, because the mean of its divisors is an integer number (351756158166).

Almost surely, 2^{1401441201331} is an apocalyptic number.

1401441201331 is a deficient number, since it is larger than the sum of its proper divisors (5583431333).

1401441201331 is an equidigital number, since it uses as much as digits as its factorization.

1401441201331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5583431332.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1401441201331 its reverse (1331021441041), we get a palindrome (2732462642372).

The spelling of 1401441201331 in words is "one trillion, four hundred one billion, four hundred forty-one million, two hundred one thousand, three hundred thirty-one".