Base | Representation |
---|---|
bin | 11010000110101110… |
… | …11110100110111111 |
3 | 1100011201221101002122 |
4 | 31003113132212333 |
5 | 212200333130142 |
6 | 10234412513155 |
7 | 1004210432312 |
oct | 150327364677 |
9 | 40151841078 |
10 | 14015130047 |
11 | 5a421a2706 |
12 | 287177b7bb |
13 | 14247a8779 |
14 | 96d4d4979 |
15 | 5706211d2 |
hex | 3435de9bf |
14015130047 has 4 divisors (see below), whose sum is σ = 14076870936. Its totient is φ = 13953389160.
The previous prime is 14015130013. The next prime is 14015130053. The reversal of 14015130047 is 74003151041.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74003151041 = 821 ⋅90137821.
It is a cyclic number.
It is not a de Polignac number, because 14015130047 - 212 = 14015125951 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14015129998 and 14015130025.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14015130007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30870104 + ... + 30870557.
It is an arithmetic number, because the mean of its divisors is an integer number (3519217734).
Almost surely, 214015130047 is an apocalyptic number.
14015130047 is a deficient number, since it is larger than the sum of its proper divisors (61740889).
14015130047 is an equidigital number, since it uses as much as digits as its factorization.
14015130047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61740888.
The product of its (nonzero) digits is 1680, while the sum is 26.
Adding to 14015130047 its reverse (74003151041), we get a palindrome (88018281088).
The spelling of 14015130047 in words is "fourteen billion, fifteen million, one hundred thirty thousand, forty-seven".
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