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14015130047 = 22761740661
BaseRepresentation
bin11010000110101110…
…11110100110111111
31100011201221101002122
431003113132212333
5212200333130142
610234412513155
71004210432312
oct150327364677
940151841078
1014015130047
115a421a2706
12287177b7bb
1314247a8779
1496d4d4979
155706211d2
hex3435de9bf

14015130047 has 4 divisors (see below), whose sum is σ = 14076870936. Its totient is φ = 13953389160.

The previous prime is 14015130013. The next prime is 14015130053. The reversal of 14015130047 is 74003151041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74003151041 = 82190137821.

It is a cyclic number.

It is not a de Polignac number, because 14015130047 - 212 = 14015125951 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14015129998 and 14015130025.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14015130007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30870104 + ... + 30870557.

It is an arithmetic number, because the mean of its divisors is an integer number (3519217734).

Almost surely, 214015130047 is an apocalyptic number.

14015130047 is a deficient number, since it is larger than the sum of its proper divisors (61740889).

14015130047 is an equidigital number, since it uses as much as digits as its factorization.

14015130047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61740888.

The product of its (nonzero) digits is 1680, while the sum is 26.

Adding to 14015130047 its reverse (74003151041), we get a palindrome (88018281088).

The spelling of 14015130047 in words is "fourteen billion, fifteen million, one hundred thirty thousand, forty-seven".

Divisors: 1 227 61740661 14015130047