14015132425345 has 4 divisors (see below), whose sum is σ = 16818158910420. Its totient is φ = 11212105940272.

The previous prime is 14015132425337. The next prime is 14015132425363. The reversal of 14015132425345 is 54352423151041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5714925329281 + 8300207096064 = 2390591^2 + 2881008^2 .

It is a cyclic number.

It is not a de Polignac number, because 14015132425345 - 2³ = 14015132425337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14015132425298 and 14015132425307.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1401513242530 + ... + 1401513242539.

It is an arithmetic number, because the mean of its divisors is an integer number (4204539727605).

Almost surely, 2^{14015132425345} is an apocalyptic number.

It is an amenable number.

14015132425345 is a deficient number, since it is larger than the sum of its proper divisors (2803026485075).

14015132425345 is an equidigital number, since it uses as much as digits as its factorization.

14015132425345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2803026485074.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 14015132425345 its reverse (54352423151041), we get a palindrome (68367555576386).

The spelling of 14015132425345 in words is "fourteen trillion, fifteen billion, one hundred thirty-two million, four hundred twenty-five thousand, three hundred forty-five".