14015132425363 has 2 divisors, whose sum is σ = 14015132425364. Its totient is φ = 14015132425362.

The previous prime is 14015132425337. The next prime is 14015132425397. The reversal of 14015132425363 is 36352423151041.

It is a weak prime.

It is an emirp because it is prime and its reverse (36352423151041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14015132425363 - 2³⁷ = 13877693471891 is a prime.

It is a super-3 number, since 3×14015132425363³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14015132425303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7007566212681 + 7007566212682.

It is an arithmetic number, because the mean of its divisors is an integer number (7007566212682).

Almost surely, 2^{14015132425363} is an apocalyptic number.

14015132425363 is a deficient number, since it is larger than the sum of its proper divisors (1).

14015132425363 is an equidigital number, since it uses as much as digits as its factorization.

14015132425363 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 14015132425363 in words is "fourteen trillion, fifteen billion, one hundred thirty-two million, four hundred twenty-five thousand, three hundred sixty-three".