1401515531041 has 4 divisors (see below), whose sum is σ = 1401517942084. Its totient is φ = 1401513120000.

The previous prime is 1401515531029. The next prime is 1401515531047. The reversal of 1401515531041 is 1401355151041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 428135971041 + 973379560000 = 654321^2 + 986600^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401515531041 - 2²³ = 1401507142433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1401515530994 and 1401515531012.

It is not an unprimeable number, because it can be changed into a prime (1401515531047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261481 + ... + 1694521.

It is an arithmetic number, because the mean of its divisors is an integer number (350379485521).

Almost surely, 2^{1401515531041} is an apocalyptic number.

It is an amenable number.

1401515531041 is a deficient number, since it is larger than the sum of its proper divisors (2411043).

1401515531041 is an equidigital number, since it uses as much as digits as its factorization.

1401515531041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2411042.

The product of its (nonzero) digits is 6000, while the sum is 31.

The spelling of 1401515531041 in words is "one trillion, four hundred one billion, five hundred fifteen million, five hundred thirty-one thousand, forty-one".