Base | Representation |
---|---|
bin | 10100011001010000010… |
… | …101011101101100100001 |
3 | 11221222112102221120012222 |
4 | 110121100111131230201 |
5 | 140430241312024213 |
6 | 2551502110000425 |
7 | 203153440103216 |
oct | 24312025355441 |
9 | 4858472846188 |
10 | 1401507142433 |
11 | 4a0415276752 |
12 | 1a7755aa6115 |
13 | a2213c2a128 |
14 | 4bb9484bb0d |
15 | 266ca61a808 |
hex | 1465055db21 |
1401507142433 has 2 divisors, whose sum is σ = 1401507142434. Its totient is φ = 1401507142432.
The previous prime is 1401507142411. The next prime is 1401507142439. The reversal of 1401507142433 is 3342417051041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1320368759329 + 81138383104 = 1149073^2 + 284848^2 .
It is a cyclic number.
It is not a de Polignac number, because 1401507142433 - 214 = 1401507126049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1401507142393 and 1401507142402.
It is not a weakly prime, because it can be changed into another prime (1401507142439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700753571216 + 700753571217.
It is an arithmetic number, because the mean of its divisors is an integer number (700753571217).
Almost surely, 21401507142433 is an apocalyptic number.
It is an amenable number.
1401507142433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401507142433 is an equidigital number, since it uses as much as digits as its factorization.
1401507142433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 35.
The spelling of 1401507142433 in words is "one trillion, four hundred one billion, five hundred seven million, one hundred forty-two thousand, four hundred thirty-three".
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