140171600113 has 4 divisors (see below), whose sum is σ = 140177378880. Its totient is φ = 140165821348.

The previous prime is 140171600087. The next prime is 140171600117. The reversal of 140171600113 is 311006171041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311006171041 = 3623 ⋅85842167.

It is a cyclic number.

It is not a de Polignac number, because 140171600113 - 2¹³ = 140171591921 is a prime.

It is a super-2 number, since 2×140171600113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140171600117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2852845 + ... + 2901562.

It is an arithmetic number, because the mean of its divisors is an integer number (35044344720).

Almost surely, 2^140171600113 is an apocalyptic number.

It is an amenable number.

140171600113 is a deficient number, since it is larger than the sum of its proper divisors (5778767).

140171600113 is an equidigital number, since it uses as much as digits as its factorization.

140171600113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5778766.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 140171600113 its reverse (311006171041), we get a palindrome (451177771154).

The spelling of 140171600113 in words is "one hundred forty billion, one hundred seventy-one million, six hundred thousand, one hundred thirteen".