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1402002400341 = 33079831548587
BaseRepresentation
bin10100011001101101110…
…110101110010001010101
311222000210221212021100110
4110121231312232101111
5140432300103302331
62552023201033233
7203201632526634
oct24315566562125
94860727767313
101402002400341
114a0649894304
121a7873925819
13a229271194a
144bc0052b51b
1526708d48946
hex1466ddae455

1402002400341 has 16 divisors (see below), whose sum is σ = 1877334649344. Its totient is φ = 930675408624.

The previous prime is 1402002400313. The next prime is 1402002400423. The reversal of 1402002400341 is 1430042002041.

It is not a de Polignac number, because 1402002400341 - 213 = 1402002392149 is a prime.

It is a super-2 number, since 2×14020024003412 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1402002400301) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 131050 + ... + 1679636.

It is an arithmetic number, because the mean of its divisors is an integer number (117333415584).

Almost surely, 21402002400341 is an apocalyptic number.

It is an amenable number.

1402002400341 is a deficient number, since it is larger than the sum of its proper divisors (475332249003).

1402002400341 is a wasteful number, since it uses less digits than its factorization.

1402002400341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1549880.

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 1402002400341 its reverse (1430042002041), we get a palindrome (2832044402382).

The spelling of 1402002400341 in words is "one trillion, four hundred two billion, two million, four hundred thousand, three hundred forty-one".

Divisors: 1 3 307 921 983 2949 301781 905343 1548587 4645761 475416209 1426248627 1522261021 4566783063 467334133447 1402002400341