Base | Representation |
---|---|
bin | 11010000111010101… |
… | …00011010110110111 |
3 | 1100012002100102001122 |
4 | 31003222203112313 |
5 | 212203123131411 |
6 | 10235112014155 |
7 | 1004301066152 |
oct | 150352432667 |
9 | 40162312048 |
10 | 14020130231 |
11 | 5a44aa8398 |
12 | 287339135b |
13 | 1425839663 |
14 | 970036c99 |
15 | 570cac9db |
hex | 343aa35b7 |
14020130231 has 4 divisors (see below), whose sum is σ = 14844843792. Its totient is φ = 13195416672.
The previous prime is 14020130219. The next prime is 14020130269. The reversal of 14020130231 is 13203102041.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13203102041 = 10067 ⋅1311523.
It is a cyclic number.
It is not a de Polignac number, because 14020130231 - 230 = 12946388407 is a prime.
It is a super-2 number, since 2×140201302312 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 824713543 = 14020130231 / (1 + 4 + 0 + 2 + 0 + 1 + 3 + 0 + 2 + 3 + 1).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14020130281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412356755 + ... + 412356788.
It is an arithmetic number, because the mean of its divisors is an integer number (3711210948).
Almost surely, 214020130231 is an apocalyptic number.
14020130231 is a deficient number, since it is larger than the sum of its proper divisors (824713561).
14020130231 is an equidigital number, since it uses as much as digits as its factorization.
14020130231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 824713560.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 14020130231 its reverse (13203102041), we get a palindrome (27223232272).
The spelling of 14020130231 in words is "fourteen billion, twenty million, one hundred thirty thousand, two hundred thirty-one".
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