1402020121433 has 24 divisors (see below), whose sum is σ = 1568204383200. Its totient is φ = 1249719902208.

The previous prime is 1402020121427. The next prime is 1402020121451. The reversal of 1402020121433 is 3341210202041.

It is not a de Polignac number, because 1402020121433 - 2¹⁰ = 1402020120409 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1402020121399 and 1402020121408.

It is not an unprimeable number, because it can be changed into a prime (1402020121493) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18945458 + ... + 19019316.

It is an arithmetic number, because the mean of its divisors is an integer number (65341849300).

Almost surely, 2^{1402020121433} is an apocalyptic number.

It is an amenable number.

1402020121433 is a deficient number, since it is larger than the sum of its proper divisors (166184261767).

1402020121433 is a wasteful number, since it uses less digits than its factorization.

1402020121433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77369 (or 77352 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1402020121433 its reverse (3341210202041), we get a palindrome (4743230323474).

The spelling of 1402020121433 in words is "one trillion, four hundred two billion, twenty million, one hundred twenty-one thousand, four hundred thirty-three".