140204330221 has 4 divisors (see below), whose sum is σ = 140263217244. Its totient is φ = 140145443200.

The previous prime is 140204330207. The next prime is 140204330243. The reversal of 140204330221 is 122033402041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 122033402041 = 677 ⋅180256133.

It can be written as a sum of positive squares in 2 ways, for example, as 26001562500 + 114202767721 = 161250^2 + 337939^2 .

It is a cyclic number.

It is not a de Polignac number, because 140204330221 - 2⁷ = 140204330093 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140204330192 and 140204330201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140204330821) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29439940 + ... + 29444701.

It is an arithmetic number, because the mean of its divisors is an integer number (35065804311).

Almost surely, 2^140204330221 is an apocalyptic number.

It is an amenable number.

140204330221 is a deficient number, since it is larger than the sum of its proper divisors (58887023).

140204330221 is an equidigital number, since it uses as much as digits as its factorization.

140204330221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58887022.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 140204330221 its reverse (122033402041), we get a palindrome (262237732262).

The spelling of 140204330221 in words is "one hundred forty billion, two hundred four million, three hundred thirty thousand, two hundred twenty-one".