1402073044231 has 4 divisors (see below), whose sum is σ = 1402098882912. Its totient is φ = 1402047205552.

The previous prime is 1402073044219. The next prime is 1402073044283. The reversal of 1402073044231 is 1324403702041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1402073044231 - 2⁵ = 1402073044199 is a prime.

It is a super-2 number, since 2×1402073044231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1402073044193 and 1402073044202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1402073048231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12837775 + ... + 12946528.

It is an arithmetic number, because the mean of its divisors is an integer number (350524720728).

Almost surely, 2^{1402073044231} is an apocalyptic number.

1402073044231 is a deficient number, since it is larger than the sum of its proper divisors (25838681).

1402073044231 is an equidigital number, since it uses as much as digits as its factorization.

1402073044231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25838680.

The product of its (nonzero) digits is 16128, while the sum is 31.

Adding to 1402073044231 its reverse (1324403702041), we get a palindrome (2726476746272).

The spelling of 1402073044231 in words is "one trillion, four hundred two billion, seventy-three million, forty-four thousand, two hundred thirty-one".