Base | Representation |
---|---|
bin | 11111111000010101001110… |
… | …111010100001011100100011 |
3 | 200101102222220000002211120120 |
4 | 133320111032322201130203 |
5 | 121334202132010421430 |
6 | 1214111455012211323 |
7 | 41350606450130313 |
oct | 3770251672413443 |
9 | 611388800084516 |
10 | 140210531342115 |
11 | 40747a52730673 |
12 | 138858a7309b43 |
13 | 6030a47826c50 |
14 | 268a323d25443 |
15 | 11322e72c8610 |
hex | 7f854eea1723 |
140210531342115 has 64 divisors (see below), whose sum is σ = 254382439234560. Its totient is φ = 65374848161280.
The previous prime is 140210531342113. The next prime is 140210531342209. The reversal of 140210531342115 is 511243135012041.
It is not a de Polignac number, because 140210531342115 - 21 = 140210531342113 is a prime.
It is not an unprimeable number, because it can be changed into a prime (140210531342113) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7366425 + ... + 18294405.
It is an arithmetic number, because the mean of its divisors is an integer number (3974725613040).
Almost surely, 2140210531342115 is an apocalyptic number.
140210531342115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
140210531342115 is a deficient number, since it is larger than the sum of its proper divisors (114171907892445).
140210531342115 is a wasteful number, since it uses less digits than its factorization.
140210531342115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10931484.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 140210531342115 its reverse (511243135012041), we get a palindrome (651453666354156).
The spelling of 140210531342115 in words is "one hundred forty trillion, two hundred ten billion, five hundred thirty-one million, three hundred forty-two thousand, one hundred fifteen".
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