140213100324343 has 4 divisors (see below), whose sum is σ = 141236553611520. Its totient is φ = 139189647037168.

The previous prime is 140213100324301. The next prime is 140213100324431. The reversal of 140213100324343 is 343423001312041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140213100324343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140213100324643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511726643383 + ... + 511726643656.

It is an arithmetic number, because the mean of its divisors is an integer number (35309138402880).

Almost surely, 2^{140213100324343} is an apocalyptic number.

140213100324343 is a deficient number, since it is larger than the sum of its proper divisors (1023453287177).

140213100324343 is a wasteful number, since it uses less digits than its factorization.

140213100324343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1023453287176.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 140213100324343 its reverse (343423001312041), we get a palindrome (483636101636384).

The spelling of 140213100324343 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred million, three hundred twenty-four thousand, three hundred forty-three".