Search a number
-
+
140220135551 = 152179214703
BaseRepresentation
bin1000001010010111000…
…1010111100001111111
3111101221011220220221202
42002211301113201333
54244132323314201
6144225524050115
713062533325626
oct2024561274177
9441834826852
10140220135551
115451567a251
122321353393b
13102b8379312
146b029726bd
1539aa206c6b
hex20a5c5787f

140220135551 has 4 divisors (see below), whose sum is σ = 140229365472. Its totient is φ = 140210905632.

The previous prime is 140220135499. The next prime is 140220135563. The reversal of 140220135551 is 155531022041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140220135551 - 222 = 140215941247 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140220131551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4592135 + ... + 4622568.

It is an arithmetic number, because the mean of its divisors is an integer number (35057341368).

Almost surely, 2140220135551 is an apocalyptic number.

140220135551 is a deficient number, since it is larger than the sum of its proper divisors (9229921).

140220135551 is an equidigital number, since it uses as much as digits as its factorization.

140220135551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9229920.

The product of its (nonzero) digits is 6000, while the sum is 29.

Adding to 140220135551 its reverse (155531022041), we get a palindrome (295751157592).

The spelling of 140220135551 in words is "one hundred forty billion, two hundred twenty million, one hundred thirty-five thousand, five hundred fifty-one".

Divisors: 1 15217 9214703 140220135551