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14022040443423 = 34674013481141
BaseRepresentation
bin1100110000001100001010…
…1111010101101000011111
31211122111100002220111011220
43030003002233111220133
53314214114323142143
645453345250144423
72645026143132105
oct314030257255037
954574302814156
1014022040443423
114516794304a91
1216a5694b82113
137a937129654c
14366955739c75
15194b2ad69d83
hexcc0c2bd5a1f

14022040443423 has 4 divisors (see below), whose sum is σ = 18696053924568. Its totient is φ = 9348026962280.

The previous prime is 14022040443421. The next prime is 14022040443493. The reversal of 14022040443423 is 32434404022041.

14022040443423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14022040443423 - 21 = 14022040443421 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14022040443421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2337006740568 + ... + 2337006740573.

It is an arithmetic number, because the mean of its divisors is an integer number (4674013481142).

Almost surely, 214022040443423 is an apocalyptic number.

14022040443423 is a deficient number, since it is larger than the sum of its proper divisors (4674013481145).

14022040443423 is an equidigital number, since it uses as much as digits as its factorization.

14022040443423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4674013481144.

The product of its (nonzero) digits is 73728, while the sum is 33.

Adding to 14022040443423 its reverse (32434404022041), we get a palindrome (46456444465464).

The spelling of 14022040443423 in words is "fourteen trillion, twenty-two billion, forty million, four hundred forty-three thousand, four hundred twenty-three".

Divisors: 1 3 4674013481141 14022040443423