Base | Representation |
---|---|
bin | 11010000111100100… |
… | …01100111001101011 |
3 | 1100012020010021122021 |
4 | 31003302030321223 |
5 | 212204131313103 |
6 | 10235223005311 |
7 | 1004324120143 |
oct | 150362147153 |
9 | 40166107567 |
10 | 14022135403 |
11 | 5a46147961 |
12 | 2873b99837 |
13 | 142608c253 |
14 | 9703d9923 |
15 | 571056bbd |
hex | 343c8ce6b |
14022135403 has 4 divisors (see below), whose sum is σ = 14631793488. Its totient is φ = 13412477320.
The previous prime is 14022135397. The next prime is 14022135427. The reversal of 14022135403 is 30453122041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14022135403 - 25 = 14022135371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14022135443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 304829008 + ... + 304829053.
It is an arithmetic number, because the mean of its divisors is an integer number (3657948372).
Almost surely, 214022135403 is an apocalyptic number.
14022135403 is a deficient number, since it is larger than the sum of its proper divisors (609658085).
14022135403 is an equidigital number, since it uses as much as digits as its factorization.
14022135403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 609658084.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 14022135403 its reverse (30453122041), we get a palindrome (44475257444).
The spelling of 14022135403 in words is "fourteen billion, twenty-two million, one hundred thirty-five thousand, four hundred three".
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