14022313000041 has 8 divisors (see below), whose sum is σ = 19049179924800. Its totient is φ = 9171827370992.

The previous prime is 14022313000001. The next prime is 14022313000057. The reversal of 14022313000041 is 14000031322041.

14022313000041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14022313000041 - 2³⁰ = 14021239258217 is a prime.

It is a super-2 number, since 2×14022313000041² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14022312999981 and 14022313000017.

It is not an unprimeable number, because it can be changed into a prime (14022313000001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44095323741 + ... + 44095324058.

It is an arithmetic number, because the mean of its divisors is an integer number (2381147490600).

Almost surely, 2^{14022313000041} is an apocalyptic number.

It is an amenable number.

14022313000041 is a deficient number, since it is larger than the sum of its proper divisors (5026866924759).

14022313000041 is an equidigital number, since it uses as much as digits as its factorization.

14022313000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 88190647855.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14022313000041 its reverse (14000031322041), we get a palindrome (28022344322082).

The spelling of 14022313000041 in words is "fourteen trillion, twenty-two billion, three hundred thirteen million, forty-one", and thus it is an aban number.