140223221111131 has 8 divisors (see below), whose sum is σ = 148631464678320. Its totient is φ = 131832735187968.

The previous prime is 140223221111053. The next prime is 140223221111159. The reversal of 140223221111131 is 131111122322041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140223221111131 - 2¹⁵ = 140223221078363 is a prime.

It is a super-2 number, since 2×140223221111131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140223221111096 and 140223221111105.

It is not an unprimeable number, because it can be changed into a prime (140223221111191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4439394741 + ... + 4439426326.

It is an arithmetic number, because the mean of its divisors is an integer number (18578933084790).

Almost surely, 2^{140223221111131} is an apocalyptic number.

140223221111131 is a deficient number, since it is larger than the sum of its proper divisors (8408243567189).

140223221111131 is an equidigital number, since it uses as much as digits as its factorization.

140223221111131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8878822013.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 140223221111131 its reverse (131111122322041), we get a palindrome (271334343433172).

The spelling of 140223221111131 in words is "one hundred forty trillion, two hundred twenty-three billion, two hundred twenty-one million, one hundred eleven thousand, one hundred thirty-one".