Base | Representation |
---|---|
bin | 1100110000001101111101… |
… | …0111001101001000110111 |
3 | 1211122112120120111211121011 |
4 | 3030003133113031020313 |
5 | 3314221110242001224 |
6 | 45453505042533051 |
7 | 2645044063645051 |
oct | 314033727151067 |
9 | 54575516454534 |
10 | 14022520656439 |
11 | 4516a10387149 |
12 | 16a57a9967187 |
13 | 7a9419911169 |
14 | 36699d4208d1 |
15 | 194b580c5394 |
hex | cc0df5cd237 |
14022520656439 has 4 divisors (see below), whose sum is σ = 14022686646720. Its totient is φ = 14022354666160.
The previous prime is 14022520656407. The next prime is 14022520656451. The reversal of 14022520656439 is 93465602522041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14022520656439 - 25 = 14022520656407 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14022520656392 and 14022520656401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14022520653439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82868359 + ... + 83037400.
It is an arithmetic number, because the mean of its divisors is an integer number (3505671661680).
Almost surely, 214022520656439 is an apocalyptic number.
14022520656439 is a deficient number, since it is larger than the sum of its proper divisors (165990281).
14022520656439 is an equidigital number, since it uses as much as digits as its factorization.
14022520656439 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 165990280.
The product of its (nonzero) digits is 3110400, while the sum is 49.
The spelling of 14022520656439 in words is "fourteen trillion, twenty-two billion, five hundred twenty million, six hundred fifty-six thousand, four hundred thirty-nine".
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