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140225514251555 = 5113692466804719
BaseRepresentation
bin11111111000100011001011…
…111101110010010100100011
3200101111102120012002111102102
4133320203023331302110203
5121334423323122022210
61214122413440041015
741351646651556115
oct3770431375622443
9611442505074372
10140225514251555
114075334113a257
121388878900316b
13603229496ac35
14268ad45b7b3b5
1511328c2863ea5
hex7f88cbf72523

140225514251555 has 8 divisors (see below), whose sum is σ = 168285417998400. Its totient is φ = 112170544136896.

The previous prime is 140225514251521. The next prime is 140225514251591. The reversal of 140225514251555 is 555152415522041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140225514251555 - 26 = 140225514251491 is a prime.

It is a super-2 number, since 2×1402255142515552 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1233345515 + ... + 1233459204.

It is an arithmetic number, because the mean of its divisors is an integer number (21035677249800).

Almost surely, 2140225514251555 is an apocalyptic number.

140225514251555 is a deficient number, since it is larger than the sum of its proper divisors (28059903746845).

140225514251555 is a wasteful number, since it uses less digits than its factorization.

140225514251555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2466816093.

The product of its (nonzero) digits is 2000000, while the sum is 47.

Adding to 140225514251555 its reverse (555152415522041), we get a palindrome (695377929773596).

The spelling of 140225514251555 in words is "one hundred forty trillion, two hundred twenty-five billion, five hundred fourteen million, two hundred fifty-one thousand, five hundred fifty-five".

Divisors: 1 5 11369 56845 2466804719 12334023595 28045102850311 140225514251555