Base | Representation |
---|---|
bin | 1100110000001111111001… |
… | …1101100001000000110011 |
3 | 1211122120220221021101020211 |
4 | 3030003332131201000303 |
5 | 3314223142323420103 |
6 | 45454032521444551 |
7 | 2645063030511124 |
oct | 314037635410063 |
9 | 54576827241224 |
10 | 14023042404403 |
11 | 451715894810a |
12 | 16a5914640757 |
13 | 7a94a0a3c176 |
14 | 366a0c83804b |
15 | 194b88cd736d |
hex | cc0fe761033 |
14023042404403 has 4 divisors (see below), whose sum is σ = 14321405008800. Its totient is φ = 13724679800008.
The previous prime is 14023042404359. The next prime is 14023042404419. The reversal of 14023042404403 is 30440424032041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14023042404403 - 29 = 14023042403891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14023042404463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149181302128 + ... + 149181302221.
It is an arithmetic number, because the mean of its divisors is an integer number (3580351252200).
Almost surely, 214023042404403 is an apocalyptic number.
14023042404403 is a deficient number, since it is larger than the sum of its proper divisors (298362604397).
14023042404403 is an equidigital number, since it uses as much as digits as its factorization.
14023042404403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 298362604396.
The product of its (nonzero) digits is 36864, while the sum is 31.
Adding to 14023042404403 its reverse (30440424032041), we get a palindrome (44463466436444).
The spelling of 14023042404403 in words is "fourteen trillion, twenty-three billion, forty-two million, four hundred four thousand, four hundred three".
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