140233434031021 has 4 divisors (see below), whose sum is σ = 144757093193344. Its totient is φ = 135709774868700.

The previous prime is 140233434030923. The next prime is 140233434031037. The reversal of 140233434031021 is 120130434332041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140233434031021 - 2¹¹ = 140233434028973 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 4523659162291 = 140233434031021 / (1 + 4 + 0 + 2 + 3 + 3 + 4 + 3 + 4 + 0 + 3 + 1 + 0 + 2 + 1).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140233434031091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2261829581115 + ... + 2261829581176.

It is an arithmetic number, because the mean of its divisors is an integer number (36189273298336).

Almost surely, 2^{140233434031021} is an apocalyptic number.

It is an amenable number.

140233434031021 is a deficient number, since it is larger than the sum of its proper divisors (4523659162323).

140233434031021 is an equidigital number, since it uses as much as digits as its factorization.

140233434031021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4523659162322.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 140233434031021 its reverse (120130434332041), we get a palindrome (260363868363062).

The spelling of 140233434031021 in words is "one hundred forty trillion, two hundred thirty-three billion, four hundred thirty-four million, thirty-one thousand, twenty-one".