14023412422031 has 4 divisors (see below), whose sum is σ = 14023423181592. Its totient is φ = 14023401662472.

The previous prime is 14023412421979. The next prime is 14023412422069. The reversal of 14023412422031 is 13022421432041.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14023412422031 is a prime.

It is a super-2 number, since 2×14023412422031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14023412421985 and 14023412422003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14023412422631) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3103805 + ... + 6138438.

It is an arithmetic number, because the mean of its divisors is an integer number (3505855795398).

Almost surely, 2^{14023412422031} is an apocalyptic number.

14023412422031 is a deficient number, since it is larger than the sum of its proper divisors (10759561).

14023412422031 is an equidigital number, since it uses as much as digits as its factorization.

14023412422031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10759560.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 14023412422031 its reverse (13022421432041), we get a palindrome (27045833854072).

The spelling of 14023412422031 in words is "fourteen trillion, twenty-three billion, four hundred twelve million, four hundred twenty-two thousand, thirty-one".