Base | Representation |
---|---|
bin | 11111111000110000101100… |
… | …101001000110010000100011 |
3 | 200101112211000012022202211121 |
4 | 133320300230221012100203 |
5 | 121340143030401320120 |
6 | 1214133213140353111 |
7 | 41353002313116244 |
oct | 3770605451062043 |
9 | 611484005282747 |
10 | 140240021120035 |
11 | 40759505966261 |
12 | 1388b5573a5797 |
13 | 6033767298295 |
14 | 268b9206b6ccb |
15 | 1132e7121a5aa |
hex | 7f8c2ca46423 |
140240021120035 has 16 divisors (see below), whose sum is σ = 168331721594400. Its totient is φ = 112162888062720.
The previous prime is 140240021119999. The next prime is 140240021120039. The reversal of 140240021120035 is 530021120042041.
It is a de Polignac number, because none of the positive numbers 2k-140240021120035 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140240021119991 and 140240021120009.
It is not an unprimeable number, because it can be changed into a prime (140240021120039) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 645917695 + ... + 646134775.
It is an arithmetic number, because the mean of its divisors is an integer number (10520732599650).
Almost surely, 2140240021120035 is an apocalyptic number.
140240021120035 is a deficient number, since it is larger than the sum of its proper divisors (28091700474365).
140240021120035 is a wasteful number, since it uses less digits than its factorization.
140240021120035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 250038.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 140240021120035 its reverse (530021120042041), we get a palindrome (670261141162076).
The spelling of 140240021120035 in words is "one hundred forty trillion, two hundred forty billion, twenty-one million, one hundred twenty thousand, thirty-five".
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