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140240021120035 = 5454928403217081
BaseRepresentation
bin11111111000110000101100…
…101001000110010000100011
3200101112211000012022202211121
4133320300230221012100203
5121340143030401320120
61214133213140353111
741353002313116244
oct3770605451062043
9611484005282747
10140240021120035
1140759505966261
121388b5573a5797
136033767298295
14268b9206b6ccb
151132e7121a5aa
hex7f8c2ca46423

140240021120035 has 16 divisors (see below), whose sum is σ = 168331721594400. Its totient is φ = 112162888062720.

The previous prime is 140240021119999. The next prime is 140240021120039. The reversal of 140240021120035 is 530021120042041.

It is a de Polignac number, because none of the positive numbers 2k-140240021120035 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140240021119991 and 140240021120009.

It is not an unprimeable number, because it can be changed into a prime (140240021120039) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 645917695 + ... + 646134775.

It is an arithmetic number, because the mean of its divisors is an integer number (10520732599650).

Almost surely, 2140240021120035 is an apocalyptic number.

140240021120035 is a deficient number, since it is larger than the sum of its proper divisors (28091700474365).

140240021120035 is a wasteful number, since it uses less digits than its factorization.

140240021120035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 250038.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 140240021120035 its reverse (530021120042041), we get a palindrome (670261141162076).

The spelling of 140240021120035 in words is "one hundred forty trillion, two hundred forty billion, twenty-one million, one hundred twenty thousand, thirty-five".

Divisors: 1 5 4549 22745 28403 142015 217081 1085405 129205247 646026235 987501469 4937507345 6165751643 30828758215 28048004224007 140240021120035