Base | Representation |
---|---|
bin | 1100110000010011100110… |
… | …0000011000001011101011 |
3 | 1211122200110222021101020020 |
4 | 3030010321200120023223 |
5 | 3314232204422313121 |
6 | 45454315105531523 |
7 | 2645126416515234 |
oct | 314047140301353 |
9 | 54580428241206 |
10 | 14024033010411 |
11 | 4517617035066 |
12 | 16a5b50343ba3 |
13 | 7a95cb03a578 |
14 | 366aa421c08b |
15 | 194be5c601c6 |
hex | cc1398182eb |
14024033010411 has 4 divisors (see below), whose sum is σ = 18698710680552. Its totient is φ = 9349355340272.
The previous prime is 14024033010391. The next prime is 14024033010413. The reversal of 14024033010411 is 11401033042041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14024033010411 - 210 = 14024033009387 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14024033010413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2337338835066 + ... + 2337338835071.
It is an arithmetic number, because the mean of its divisors is an integer number (4674677670138).
Almost surely, 214024033010411 is an apocalyptic number.
14024033010411 is a deficient number, since it is larger than the sum of its proper divisors (4674677670141).
14024033010411 is an equidigital number, since it uses as much as digits as its factorization.
14024033010411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4674677670140.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 14024033010411 its reverse (11401033042041), we get a palindrome (25425066052452).
The spelling of 14024033010411 in words is "fourteen trillion, twenty-four billion, thirty-three million, ten thousand, four hundred eleven".
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