140244334111331 has 4 divisors (see below), whose sum is σ = 140244388235112. Its totient is φ = 140244279987552.

The previous prime is 140244334111283. The next prime is 140244334111339. The reversal of 140244334111331 is 133111433442041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140244334111331 is a prime.

It is a super-2 number, since 2×140244334111331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140244334111291 and 140244334111300.

It is not an unprimeable number, because it can be changed into a prime (140244334111339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22968761 + ... + 28426266.

It is an arithmetic number, because the mean of its divisors is an integer number (35061097058778).

Almost surely, 2^{140244334111331} is an apocalyptic number.

140244334111331 is a deficient number, since it is larger than the sum of its proper divisors (54123781).

140244334111331 is an equidigital number, since it uses as much as digits as its factorization.

140244334111331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54123780.

The product of its (nonzero) digits is 41472, while the sum is 35.

Adding to 140244334111331 its reverse (133111433442041), we get a palindrome (273355767553372).

The spelling of 140244334111331 in words is "one hundred forty trillion, two hundred forty-four billion, three hundred thirty-four million, one hundred eleven thousand, three hundred thirty-one".