Base | Representation |
---|---|
bin | 11111111000110100111010… |
… | …100111100000001100111111 |
3 | 200101120020200212020200010101 |
4 | 133320310322213200030333 |
5 | 121340231314420102320 |
6 | 1214135242422021531 |
7 | 41353222462463350 |
oct | 3770647247401477 |
9 | 611506625220111 |
10 | 140244550550335 |
11 | 4076041a688290 |
12 | 138904002778a7 |
13 | 60340097a765a |
14 | 268bc30083d27 |
15 | 1133138bbdc0a |
hex | 7f8d3a9e033f |
140244550550335 has 16 divisors (see below), whose sum is σ = 209820418486272. Its totient is φ = 87425174368800.
The previous prime is 140244550550333. The next prime is 140244550550417. The reversal of 140244550550335 is 533055055442041.
It is not a de Polignac number, because 140244550550335 - 21 = 140244550550333 is a prime.
It is a super-3 number, since 3×1402445505503353 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140244550550333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 182135779551 + ... + 182135780320.
It is an arithmetic number, because the mean of its divisors is an integer number (13113776155392).
Almost surely, 2140244550550335 is an apocalyptic number.
140244550550335 is a deficient number, since it is larger than the sum of its proper divisors (69575867935937).
140244550550335 is a wasteful number, since it uses less digits than its factorization.
140244550550335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 364271559894.
The product of its (nonzero) digits is 3600000, while the sum is 46.
The spelling of 140244550550335 in words is "one hundred forty trillion, two hundred forty-four billion, five hundred fifty million, five hundred fifty thousand, three hundred thirty-five".
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