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14025001541 = 127110433083
BaseRepresentation
bin11010000111111010…
…01000101001000101
31100012102111220020112
431003331020221011
5212210400022131
610235404242405
71004360355215
oct150375105105
940172456215
1014025001541
115a47825271
122874b40405
1314268539a5
14970944245
1557142102b
hex343f48a45

14025001541 has 4 divisors (see below), whose sum is σ = 14135434752. Its totient is φ = 13914568332.

The previous prime is 14025001537. The next prime is 14025001553. The reversal of 14025001541 is 14510052041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14025001541 - 22 = 14025001537 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14025001591) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55216415 + ... + 55216668.

It is an arithmetic number, because the mean of its divisors is an integer number (3533858688).

Almost surely, 214025001541 is an apocalyptic number.

It is an amenable number.

14025001541 is a deficient number, since it is larger than the sum of its proper divisors (110433211).

14025001541 is a wasteful number, since it uses less digits than its factorization.

14025001541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110433210.

The product of its (nonzero) digits is 800, while the sum is 23.

Adding to 14025001541 its reverse (14510052041), we get a palindrome (28535053582).

It can be divided in two parts, 1402500 and 1541, that added together give a palindrome (1404041).

The spelling of 14025001541 in words is "fourteen billion, twenty-five million, one thousand, five hundred forty-one".

Divisors: 1 127 110433083 14025001541