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140252531531 = 720036075933
BaseRepresentation
bin1000001010011110110…
…0111100101101001011
3111102000102212210212212
42002213230330231023
54244214122002111
6144233042255335
713063405563560
oct2024754745513
9442012783785
10140252531531
1154531996892
122322235754b
13102c1caca38
146b06da6867
1539acea598b
hex20a7b3cb4b

140252531531 has 4 divisors (see below), whose sum is σ = 160288607472. Its totient is φ = 120216455592.

The previous prime is 140252531501. The next prime is 140252531533. The reversal of 140252531531 is 135135252041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140252531531 - 218 = 140252269387 is a prime.

It is a super-2 number, since 2×1402525315312 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (140252531533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10018037960 + ... + 10018037973.

It is an arithmetic number, because the mean of its divisors is an integer number (40072151868).

Almost surely, 2140252531531 is an apocalyptic number.

140252531531 is a deficient number, since it is larger than the sum of its proper divisors (20036075941).

140252531531 is an equidigital number, since it uses as much as digits as its factorization.

140252531531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20036075940.

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 140252531531 its reverse (135135252041), we get a palindrome (275387783572).

The spelling of 140252531531 in words is "one hundred forty billion, two hundred fifty-two million, five hundred thirty-one thousand, five hundred thirty-one".

Divisors: 1 7 20036075933 140252531531