140286544799903 has 4 divisors (see below), whose sum is σ = 140287264232400. Its totient is φ = 140285825367408.

The previous prime is 140286544799893. The next prime is 140286544799917. The reversal of 140286544799903 is 309997445682041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140286544799903 - 2³⁸ = 140011666892959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140286544792903) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 359423675 + ... + 359813772.

It is an arithmetic number, because the mean of its divisors is an integer number (35071816058100).

It is a 1-persistent number, because it is pandigital, but 2⋅140286544799903 = 280573089599806 is not.

Almost surely, 2^{140286544799903} is an apocalyptic number.

140286544799903 is a deficient number, since it is larger than the sum of its proper divisors (719432497).

140286544799903 is an equidigital number, since it uses as much as digits as its factorization.

140286544799903 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 719432496.

The product of its (nonzero) digits is 470292480, while the sum is 71.

The spelling of 140286544799903 in words is "one hundred forty trillion, two hundred eighty-six billion, five hundred forty-four million, seven hundred ninety-nine thousand, nine hundred three".