Base | Representation |
---|---|
bin | 11010001000100000… |
… | …10111100000000101 |
3 | 1100012210000001000110 |
4 | 31010100113200011 |
5 | 212213142340031 |
6 | 10240104303233 |
7 | 1004451253602 |
oct | 150420274005 |
9 | 40183001013 |
10 | 14030043141 |
11 | 5a4a659084 |
12 | 2876771b19 |
13 | 14278ca69a |
14 | 9714976a9 |
15 | 571ab9c46 |
hex | 344417805 |
14030043141 has 4 divisors (see below), whose sum is σ = 18706724192. Its totient is φ = 9353362092.
The previous prime is 14030043109. The next prime is 14030043151. The reversal of 14030043141 is 14134003041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 14030043141 - 25 = 14030043109 is a prime.
It is a super-2 number, since 2×140300431412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14030043151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2338340521 + ... + 2338340526.
It is an arithmetic number, because the mean of its divisors is an integer number (4676681048).
Almost surely, 214030043141 is an apocalyptic number.
It is an amenable number.
14030043141 is a deficient number, since it is larger than the sum of its proper divisors (4676681051).
14030043141 is an equidigital number, since it uses as much as digits as its factorization.
14030043141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4676681050.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 14030043141 its reverse (14134003041), we get a palindrome (28164046182).
The spelling of 14030043141 in words is "fourteen billion, thirty million, forty-three thousand, one hundred forty-one".
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