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14030043311 = 43326280077
BaseRepresentation
bin11010001000100000…
…10111100010101111
31100012210000001020202
431010100113202233
5212213142341221
610240104304115
71004451254234
oct150420274257
940183001222
1014030043311
115a4a659219
12287677203b
1314278ca79b
1497149778b
15571ab9d0b
hex3444178af

14030043311 has 4 divisors (see below), whose sum is σ = 14356323432. Its totient is φ = 13703763192.

The previous prime is 14030043299. The next prime is 14030043317. The reversal of 14030043311 is 11334003041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14030043311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14030043317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163139996 + ... + 163140081.

It is an arithmetic number, because the mean of its divisors is an integer number (3589080858).

Almost surely, 214030043311 is an apocalyptic number.

14030043311 is a deficient number, since it is larger than the sum of its proper divisors (326280121).

14030043311 is an equidigital number, since it uses as much as digits as its factorization.

14030043311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 326280120.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 14030043311 its reverse (11334003041), we get a palindrome (25364046352).

The spelling of 14030043311 in words is "fourteen billion, thirty million, forty-three thousand, three hundred eleven".

Divisors: 1 43 326280077 14030043311