1403053473 has 4 divisors (see below), whose sum is σ = 1870737968. Its totient is φ = 935368980.

The previous prime is 1403053441. The next prime is 1403053501. The reversal of 1403053473 is 3743503041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3743503041 = 3 ⋅1247834347.

It is not a de Polignac number, because 1403053473 - 2⁵ = 1403053441 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1403053473.

It is not an unprimeable number, because it can be changed into a prime (1403053973) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233842243 + ... + 233842248.

It is an arithmetic number, because the mean of its divisors is an integer number (467684492).

Almost surely, 2^1403053473 is an apocalyptic number.

It is an amenable number.

1403053473 is a deficient number, since it is larger than the sum of its proper divisors (467684495).

1403053473 is an equidigital number, since it uses as much as digits as its factorization.

1403053473 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 467684494.

The product of its (nonzero) digits is 15120, while the sum is 30.

The square root of 1403053473 is about 37457.3553924993. The cubic root of 1403053473 is about 1119.5016578138.

The spelling of 1403053473 in words is "one billion, four hundred three million, fifty-three thousand, four hundred seventy-three".