Base | Representation |
---|---|
bin | 1000001010101101010… |
… | …1001011101110010111 |
3 | 111102011200102210001211 |
4 | 2002223111023232113 |
5 | 4244330213113310 |
6 | 144243055202251 |
7 | 13065045211261 |
oct | 2025325135627 |
9 | 442150383054 |
10 | 140313410455 |
11 | 54563298049 |
12 | 2323a816387 |
13 | 103017a6a7a |
14 | 6b110d2b31 |
15 | 39b34cdc8a |
hex | 20ab54bb97 |
140313410455 has 8 divisors (see below), whose sum is σ = 169920828000. Its totient is φ = 111220904736.
The previous prime is 140313410443. The next prime is 140313410473. The reversal of 140313410455 is 554014313041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 140313410455 - 211 = 140313408407 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 128727355 + ... + 128728444.
It is an arithmetic number, because the mean of its divisors is an integer number (21240103500).
Almost surely, 2140313410455 is an apocalyptic number.
140313410455 is a deficient number, since it is larger than the sum of its proper divisors (29607417545).
140313410455 is a wasteful number, since it uses less digits than its factorization.
140313410455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 257455913.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 140313410455 its reverse (554014313041), we get a palindrome (694327723496).
The spelling of 140313410455 in words is "one hundred forty billion, three hundred thirteen million, four hundred ten thousand, four hundred fifty-five".
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