140313413023111 has 4 divisors (see below), whose sum is σ = 140323867802424. Its totient is φ = 140302958243800.

The previous prime is 140313413023099. The next prime is 140313413023139. The reversal of 140313413023111 is 111320314313041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140313413023111 - 2⁵ = 140313413023079 is a prime.

It is a super-3 number, since 3×140313413023111³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140313413023111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140313413023141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5227369525 + ... + 5227396366.

It is an arithmetic number, because the mean of its divisors is an integer number (35080966950606).

Almost surely, 2^{140313413023111} is an apocalyptic number.

140313413023111 is a deficient number, since it is larger than the sum of its proper divisors (10454779313).

140313413023111 is a wasteful number, since it uses less digits than its factorization.

140313413023111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10454779312.

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 140313413023111 its reverse (111320314313041), we get a palindrome (251633727336152).

The spelling of 140313413023111 in words is "one hundred forty trillion, three hundred thirteen billion, four hundred thirteen million, twenty-three thousand, one hundred eleven".