Base | Representation |
---|---|
bin | 11010001000101011… |
… | …00101010000111010 |
3 | 1100012212120111022112 |
4 | 31010111211100322 |
5 | 212214020111414 |
6 | 10240153452322 |
7 | 1004466006362 |
oct | 150425452072 |
9 | 40185514275 |
10 | 14031410234 |
11 | 5a50402206 |
12 | 28771110a2 |
13 | 1427c88a0a |
14 | 9717319a2 |
15 | 571c89d3e |
hex | 34456543a |
14031410234 has 4 divisors (see below), whose sum is σ = 21047115354. Its totient is φ = 7015705116.
The previous prime is 14031410231. The next prime is 14031410243. The reversal of 14031410234 is 43201413041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 14031113209 + 297025 = 118453^2 + 545^2 .
It is not an unprimeable number, because it can be changed into a prime (14031410231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3507852557 + ... + 3507852560.
Almost surely, 214031410234 is an apocalyptic number.
14031410234 is a deficient number, since it is larger than the sum of its proper divisors (7015705120).
14031410234 is an equidigital number, since it uses as much as digits as its factorization.
14031410234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7015705119.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 14031410234 its reverse (43201413041), we get a palindrome (57232823275).
The spelling of 14031410234 in words is "fourteen billion, thirty-one million, four hundred ten thousand, two hundred thirty-four".
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