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140323454333 = 314526563043
BaseRepresentation
bin1000001010101111101…
…1011111110101111101
3111102012101100001200022
42002223323133311331
54244340301014313
6144244054341525
713065226452566
oct2025373376575
9442171301608
10140323454333
1154568a28177
122324205a8a5
13103038b25aa
146b1258916d
1539b4314c08
hex20abedfd7d

140323454333 has 4 divisors (see below), whose sum is σ = 144850017408. Its totient is φ = 135796891260.

The previous prime is 140323454251. The next prime is 140323454377. The reversal of 140323454333 is 333454323041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140323454333 - 216 = 140323388797 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140323454293 and 140323454302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140323454393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2263281491 + ... + 2263281552.

It is an arithmetic number, because the mean of its divisors is an integer number (36212504352).

Almost surely, 2140323454333 is an apocalyptic number.

It is an amenable number.

140323454333 is a deficient number, since it is larger than the sum of its proper divisors (4526563075).

140323454333 is an equidigital number, since it uses as much as digits as its factorization.

140323454333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4526563074.

The product of its (nonzero) digits is 155520, while the sum is 35.

Adding to 140323454333 its reverse (333454323041), we get a palindrome (473777777374).

The spelling of 140323454333 in words is "one hundred forty billion, three hundred twenty-three million, four hundred fifty-four thousand, three hundred thirty-three".

Divisors: 1 31 4526563043 140323454333