Base | Representation |
---|---|
bin | 1000001010110011111… |
… | …1000011110001100001 |
3 | 111102020121122212100121 |
4 | 2002230333003301201 |
5 | 4244404314241103 |
6 | 144245530120241 |
7 | 13065533135620 |
oct | 2025477036141 |
9 | 442217585317 |
10 | 140341165153 |
11 | 54577a24612 |
12 | 23247b80081 |
13 | 10307473a77 |
14 | 6b14a796b7 |
15 | 39b5b626bd |
hex | 20acfc3c61 |
140341165153 has 4 divisors (see below), whose sum is σ = 160389903040. Its totient is φ = 120292427268.
The previous prime is 140341165141. The next prime is 140341165171. The reversal of 140341165153 is 351561143041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 351561143041 = 25919 ⋅13563839.
It is a cyclic number.
It is not a de Polignac number, because 140341165153 - 233 = 131751230561 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140341165183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10024368933 + ... + 10024368946.
It is an arithmetic number, because the mean of its divisors is an integer number (40097475760).
Almost surely, 2140341165153 is an apocalyptic number.
It is an amenable number.
140341165153 is a deficient number, since it is larger than the sum of its proper divisors (20048737887).
140341165153 is an equidigital number, since it uses as much as digits as its factorization.
140341165153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20048737886.
The product of its (nonzero) digits is 21600, while the sum is 34.
The spelling of 140341165153 in words is "one hundred forty billion, three hundred forty-one million, one hundred sixty-five thousand, one hundred fifty-three".
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