140341323112141 has 4 divisors (see below), whose sum is σ = 148596695059932. Its totient is φ = 132085951164352.

The previous prime is 140341323112139. The next prime is 140341323112147. The reversal of 140341323112141 is 141211323143041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 106625346662025 + 33715976450116 = 10325955^2 + 5806546^2 .

It is a cyclic number.

It is not a de Polignac number, because 140341323112141 - 2¹ = 140341323112139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140341323112147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4127685973870 + ... + 4127685973903.

It is an arithmetic number, because the mean of its divisors is an integer number (37149173764983).

Almost surely, 2^{140341323112141} is an apocalyptic number.

It is an amenable number.

140341323112141 is a deficient number, since it is larger than the sum of its proper divisors (8255371947791).

140341323112141 is an equidigital number, since it uses as much as digits as its factorization.

140341323112141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8255371947790.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 140341323112141 its reverse (141211323143041), we get a palindrome (281552646255182).

The spelling of 140341323112141 in words is "one hundred forty trillion, three hundred forty-one billion, three hundred twenty-three million, one hundred twelve thousand, one hundred forty-one".